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2x-4=5x^2+2
We move all terms to the left:
2x-4-(5x^2+2)=0
We get rid of parentheses
-5x^2+2x-2-4=0
We add all the numbers together, and all the variables
-5x^2+2x-6=0
a = -5; b = 2; c = -6;
Δ = b2-4ac
Δ = 22-4·(-5)·(-6)
Δ = -116
Delta is less than zero, so there is no solution for the equation
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